Number of nines in "0.999999", etc, as reported by Google.
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Of course, this plot should remind you of this:
One more thing.
At the end of the last post, I asserted that:\[\sum_{i = 1}^{\infty} \frac{1}{2^i}\] also converges to 1. It's an interesting fact that in base two, 0.1111... = 1. In fact, for every base b, you can represent one as an infinite sequence of \((b-1)\)s.
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